2025-04-29 18:09:00 +08:00
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import datetime
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import numpy as np
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from ninja_extra import api_controller, ControllerBase, route
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from ninja import Query
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from ninja_jwt.authentication import JWTAuth
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from ninja_extra.permissions import IsAuthenticated
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from ninja.pagination import paginate
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from apps.dict.models import DictItem
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from utils.chen_pagination import MyPagination
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from django.db import transaction
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from typing import List, Optional
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from utils.chen_response import ChenResponse
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from utils.codes import HTTP_INDEX_ERROR
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from django.shortcuts import get_object_or_404
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from apps.project.models import Case, Problem, Project, TestDemand
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from apps.project.schemas.problem import (
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DeleteSchema,
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ProblemModelOutSchema,
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ProblemFilterSchema,
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ProblemCreateOutSchema,
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ProblemCreateInputSchema,
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ProblemSingleInputSchema,
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ProblemUpdateInputSchema,
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ProblemFilterWithHangSchema
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)
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from utils.util import get_str_abbr
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from utils.smallTools.interfaceTools import conditionNoneToBlank
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@api_controller("/project", auth=JWTAuth(), permissions=[IsAuthenticated], tags=['问题单系列'])
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class ProblemController(ControllerBase):
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@route.get("/getProblemList", response=List[ProblemModelOutSchema], exclude_none=True,
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url_name="problem-list")
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@transaction.atomic
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@paginate(MyPagination)
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def get_problem_list(self, data: ProblemFilterSchema = Query(...)):
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project_id = data.project_id
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conditionNoneToBlank(data)
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2025-12-23 10:36:55 +08:00
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# 组装查询条件
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query_params = {
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"project__id":data.project_id,
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"ident__icontains":data.ident,
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"name__icontains":data.name,
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"status__icontains":data.status,
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"type__icontains":data.type,
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"grade__icontains":data.grade,
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"operation__icontains":data.operation,
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"postPerson__icontains":data.postPerson
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}
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# 如果没有多个key传递则是汇总界面
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if data.dut_id and data.design_id and data.test_id and data.case_id:
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case_key = "".join(
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[data.round_id, '-', data.dut_id, '-', data.design_id, '-', data.test_id, '-', data.case_id])
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query_params['case__key'] = case_key
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else:
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query_params['case__round__key'] = data.round_id
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qs = Problem.objects.filter(**query_params).order_by("id")
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2025-04-29 18:09:00 +08:00
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# 遍历通过代码不通过ORM查询闭环方式-巧妙使用numpy中array对象的in方法来判断
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closeMethod1 = self.context.request.GET.get("closeMethod[0]")
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closeMethod2 = self.context.request.GET.get("closeMethod[1]")
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query_add_closeMethod = []
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for query in qs:
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arr = np.array(query.closeMethod)
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if closeMethod1 is None and closeMethod2 is None:
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query_add_closeMethod.append(query)
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continue
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if closeMethod1 in arr:
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query_add_closeMethod.append(query)
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continue
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if closeMethod2 in arr:
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query_add_closeMethod.append(query)
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continue
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return query_add_closeMethod
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# 搜索全部问题单/或查询轮次下的问题单
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@route.get('/problem/searchAllProblem', response=List[ProblemModelOutSchema], exclude_none=True,
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url_name="problem-allList")
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@transaction.atomic
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@paginate(MyPagination)
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def get_all_problems(self, round_key: Optional[str] = False, data: ProblemFilterWithHangSchema = Query(...)):
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project_id = data.project_id
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2025-12-23 10:36:55 +08:00
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conditionNoneToBlank(data)
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2025-04-29 18:09:00 +08:00
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# 先查询当前项目
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qs = Problem.objects.filter(project__id=data.project_id,
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ident__icontains=data.ident,
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name__icontains=data.name,
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status__icontains=data.status,
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type__icontains=data.type,
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grade__icontains=data.grade,
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operation__icontains=data.operation,
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postPerson__icontains=data.postPerson,
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).order_by("id")
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closeMethod1 = self.context.request.GET.get("closeMethod[0]")
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closeMethod2 = self.context.request.GET.get("closeMethod[1]")
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query_final = []
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for query in qs:
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arr = np.array(query.closeMethod)
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if closeMethod1 is None and closeMethod2 is None:
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query_final.append(query)
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continue
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if closeMethod1 in arr:
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query_final.append(query)
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continue
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if closeMethod2 in arr:
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query_final.append(query)
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continue
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# 遍历所有problem，查询是有否有关联case，如果有则设置hang为True，否则False
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hang = True
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# 过滤不是该轮次的问题单对象列表
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deleted_problem_list = []
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for pro_obj in query_final:
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case_exists = pro_obj.case.exists()
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if not case_exists:
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setattr(pro_obj, "hang", hang)
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# 如果有关联用例还要看是否是查询轮次的问题单，过滤出去
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elif case_exists:
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hang = False
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setattr(pro_obj, "hang", hang)
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hang = True
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if round_key:
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if not pro_obj.case.filter(round__key=round_key).exists():
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deleted_problem_list.append(pro_obj)
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for dq in deleted_problem_list:
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query_final.remove(dq)
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# !!!如果是轮次查询则返回轮次，如果是关联查询则查询关联当前的case
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if round_key:
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pass
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else:
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case_obj = Case.objects.filter(project_id=project_id, key=data.key).first()
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if case_obj:
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for pro_obj in query_final:
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# 查询关联的case
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related = False
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for re_case in pro_obj.case.all():
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if case_obj.id == re_case.id:
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related = True
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setattr(pro_obj, "related", related)
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# 过滤查询悬挂逻辑
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query_last = []
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if data.hang == '3' or data.hang == '': # 疑问：为什么会是空字符串
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query_last = query_final
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if data.hang == '2':
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for pp in query_final:
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if not pp.hang:
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query_last.append(pp)
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if data.hang == '1':
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for pp in query_final:
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if pp.hang is True:
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query_last.append(pp)
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return query_last
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@staticmethod
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def __date_solve(payload: ProblemCreateInputSchema):
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"""辅助函数：
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1.设置问题单时间，而不是默认进入时间，传入schema对象，返回schema对象，只对里面时间进行处理
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"""
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project_obj = get_object_or_404(Project, id=payload.project_id)
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round_obj = project_obj.pField.filter(key=payload.round_key).first()
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if round_obj:
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if payload.postDate is None:
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payload.postDate = round_obj.beginTime + datetime.timedelta(days=1)
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if payload.designDate is None:
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payload.designDate = round_obj.beginTime + datetime.timedelta(days=2)
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return payload
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# 添加问题单
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@route.post("/problem/save", response=ProblemCreateOutSchema, url_name="problem-create")
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@transaction.atomic
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def create_case_demand(self, payload: ProblemCreateInputSchema):
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payload = self.__date_solve(payload)
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asert_dict = payload.dict()
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project_id = payload.project_id
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# 查询problem的总数
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problem_count = Problem.objects.filter(project_id=project_id).count()
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# 查询当前各个前面节点的instance
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pop_keys: List[str] = ["round_key", "dut_key", "design_key", "test_key", "case_key"]
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for pkey in pop_keys:
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asert_dict.pop(pkey)
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# 处理问题单标识PT_项目ident_数目依次增加
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asert_dict["ident"] = str(problem_count + 1)
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qs = Problem.objects.create(**asert_dict)
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# 处理时间
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qs.postDate = payload.postDate
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qs.designDate = payload.designDate
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qs.save()
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# 分两个逻辑处理，无关联创建问题单/case下面创建问题单
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if payload.case_key:
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# 构造case_key
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case_key = "".join(
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[payload.round_key, "-", payload.dut_key, '-', payload.design_key, '-', payload.test_key, '-',
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payload.case_key])
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# 查询出所属的case
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case_obj = Case.objects.filter(project_id=project_id, key=case_key).first()
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qs.case.add(case_obj)
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qs.save()
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# 对problem的ident排序
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self.reset_problem_ident(project_id)
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return qs
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# 更新问题单
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@route.put("/problem/update/{id}", response=ProblemCreateOutSchema, url_name="problem-update")
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@transaction.atomic
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def update_problem(self, id: int, payload: ProblemCreateInputSchema):
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# 查到当前
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problem_qs = Problem.objects.get(id=id)
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for attr, value in payload.dict().items():
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setattr(problem_qs, attr, value)
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problem_qs.save()
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return ChenResponse(message="问题单更新成功")
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# 弹窗的-更新问题单
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@route.put("/problem/modalupdate/{id}", response=ProblemCreateOutSchema, url_name="problem-update")
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@transaction.atomic
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def update_modal_problem(self, id: int, payload: ProblemUpdateInputSchema):
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# 查到当前
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problem_qs = Problem.objects.get(id=id)
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for attr, value in payload.dict().items():
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setattr(problem_qs, attr, value)
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problem_qs.save()
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return ChenResponse(message="问题单更新成功")
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# 删除问题单
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@route.delete("/problem/delete", url_name="problem-delete")
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@transaction.atomic
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def delete_problem(self, data: DeleteSchema):
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# 1.查询出所有被删除id
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problems = Problem.objects.filter(id__in=data.ids)
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if not problems.exists():
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return ChenResponse(status=500, code=HTTP_INDEX_ERROR, message='您未选取删除内容')
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# 4.查询出当前项目id
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project_id = None
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# 2.循环该取出problem
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for problem in problems:
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project_id = problem.project_id
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# 3. 直接删除case关联，然后删除自己
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problem.case.clear()
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problem.delete()
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# 4.找到对应项目的所有problems进行排序
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if project_id is not None:
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self.reset_problem_ident(project_id)
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return ChenResponse(message="问题单删除成功！")
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# 根据问题单id，返回关联的用例s
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@route.get('/getRelativeCases', url_name='problem-relative-case')
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@transaction.atomic
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def get_relative_cases(self, id: int):
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problem_qs = get_object_or_404(Problem, id=id)
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cases = problem_qs.case.all()
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case_list = []
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for case in cases:
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case_dict = {
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'id': case.id,
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'case': case.title,
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'round': case.round.title,
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'dut': case.dut.title,
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'design': case.design.title,
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}
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demand = case.test
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case_dict['demand'] = demand.title
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demand_testType_showtitle = get_str_abbr(demand.testType, 'testType')
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case_dict['demand_ident'] = "-".join(['XQ', demand_testType_showtitle, demand.ident])
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case_list.append(case_dict)
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return case_list
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# 单独显示问题单页面需要数据
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@route.get("/getSingleProblem", url_name="problem-single", response=ProblemCreateOutSchema)
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@transaction.atomic
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def search_single_problem(self, data: ProblemSingleInputSchema = Query(...)):
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key_string = "".join(
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[data.round_id, '-', data.dut_id, '-', data.design_id, '-', data.test_id, '-', data.case_id, '-',
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data.problem_id])
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qs = Problem.objects.get(project__id=data.project_id, key=key_string)
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return qs
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# 让测试用例关联/取消问题单
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@route.get('/problem/relateProblem', exclude_none=True, url_name="problem-allList")
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@transaction.atomic
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def relate_problem(self, case_key: str, problem_id: int, val: bool): # val是将要变成的值
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# 先判断将要变成的值是否为True
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problem_obj: Problem = Problem.objects.filter(id=problem_id).first()
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project_id = problem_obj.project_id # 根据问题单反推项目id
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case_obj = Case.objects.filter(project_id=project_id, key=case_key).first()
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flag = False # 是否操作成功的标志
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if val:
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# 这分支是进行关联操作
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# 5月15日新需求：一个用例只能关联一个问题单
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if case_obj.caseField.count() >= 1:
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return ChenResponse(code=400, status=400, message='请注意：一个用例只允许关联一个问题单',
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data={'isOK': False})
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case_obj.caseField.add(problem_obj)
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flag = True
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else:
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case_obj.caseField.remove(problem_obj)
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flag = True
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# 排序ident
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if project_id:
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self.reset_problem_ident(project_id)
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return ChenResponse(code=200, status=200, message='关联或取消关联成功...',
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data={'isOK': flag, 'key': case_obj.key})
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# 类方法：操作后对problem的ident排序：先基于轮次排序，然后基于测试项类型排序
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@classmethod
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def reset_problem_ident(cls, project_id: int):
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project_obj: Project = get_object_or_404(Project, id=project_id)
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# 获取所有问题单
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problem_qs = project_obj.projField.prefetch_related('case').prefetch_related('case__test')
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# 待排序列表
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not_sorted_problems = []
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# 处理为List[Dict]以便后续排序修改ident
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for problem in problem_qs:
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cases = problem.case.all()
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if len(cases):
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# 如果关联了case
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belong_demand: TestDemand = cases[0].test
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# 找到对应测试类型
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|
test_type = DictItem.objects.get(dict__code='testType', key=belong_demand.testType)
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|
# 找到测试类型的sort/找到轮次key
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|
not_sorted_problems.append({
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|
'problem': problem,
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'sort': test_type.sort,
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|
'round_key': belong_demand.round.key,
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})
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else:
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|
# 如果没有关联case
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|
|
not_sorted_problems.append({
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|
|
'problem': problem,
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|
|
'sort': 1024,
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|
|
'round_key': 1024,
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|
})
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|
|
# 排序后修改ident
|
|
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|
|
round_sorted_problems = sorted(not_sorted_problems, key=lambda x: int(x['round_key']))
|
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|
|
last_sorted_problems = sorted(round_sorted_problems, key=lambda x: int(x['sort']))
|
|
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|
|
# 根据排序修改problem的ident
|
|
|
|
|
|
for index, problem_dict in enumerate(last_sorted_problems):
|
|
|
|
|
|
problem_dict['problem'].ident = str(index + 1)
|
|
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|
|
problem_dict['problem'].save()
|
